Meat and Potatoes

Group 1 - 9:30 Class


Group Members:

Tyler Larrivee, Blayze Markoya, Fernando Piedra, Joshua Sanford, Shawn Smith

Meat          x →     2x                    1 COH    3 VIT    3 PRO

Potatoes     y →    .75y                  3 COH    4 VIT   1 PRO




 


Diet                                               8 COH    19 VIT   7 PRO

 

 

 

Meat

Potatoes

Required

CHO

1

3

8

VIT

3

4

19

PRO

3

1

7

COST

2

.75

-

 

X = # of servings of meat per day

Y = # of servings of potatoes per day

 

CHO: x + 3y ≥ 8

VIT: 3x + 4y ≥ 19

PRO: 3x + y ≥ 7

x ≥ 0    ,     y ≥ 0

 

COST: = 2x + .75y

 

Inequality

CHO: x + 3y ≥ 8

VIT: 3x + 4y ≥ 19

PRO: 3x + y ≥ 7

x ≥ 0

y ≥ 0

 

Standard Form

y ≥ -1/3x + 8/3

y ≥ -3/4x + 19/4

y ≥ -3x + 7

x ≥ 0

y ≥ 0

 

Line

y = -1/3x + 8/3

y = -3/4x + 19/4

y = -3x + 7

x = 0

y = 0

 

Intercepts (x,y)

(8,0) , (0,8/3)

(6.3,0) , (0,19/4)

(2.33,0) , (0,7)

(0,0) , (none)

(none) , (0,0)

 

Vertex

                                 (0,7)

                                 (9/5, 17/5)

                                 (5, 1)

                                 (8,0)


 

Cost = 2x + .75y

                        (2 ∙ 0) + (.75 ∙ 7) = 5.25

                        (2 ∙ 9/5) + (.75 ∙ 17/5) = 6.15

                        (2 ∙ 5) + (.75 ∙ 1) = 10.75

                        (2 ∙ 8) + (.75 ∙ 0) = 16


 
 

(Referring to Graph 1)

 

A :       y = -3/4x + 19/4

            y = -3x + 7

B :       y = -3/4x + 19/4

            y = -1/3x + 8/3

 

 

A : -3/4x + 19/4 = -3x + 7    ,     x = 1.8

A :       1.8 , 3.4

 

B : -3/4x + 19/4 = -1/3x + 8/3    ,     x = 5

A :       5 , 1

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